Quick Answer
The vertex of y = ax² + bx + c is at x = −b ÷ 2a. Put that x back into the equation to get y. For y = 2x² − 8x + 3, x = 8 ÷ 4 = 2 and y = 8 − 16 + 3 = −5, so the vertex is (2, −5). In vertex form that is y = 2(x − 2)² − 5, a minimum because a is positive.
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Table of Contents
- Vertex Calculator
- Quick Answer
- Related Calculators
- How This Vertex Calculator Works
- How to Use the Vertex Calculator
- Vertex Formulas
- Key Terms
- Worked Example
- Real-Life Examples
- Standard Form vs Vertex Form
- Vertex Examples
- Completing the Square
- Why the Vertex Matters
- Common Mistakes to Avoid
- Frequently Asked Questions
- References & Sources
How This Vertex Calculator Works
Enter a, b and c from the standard form y = ax² + bx + c. The calculator finds the x-coordinate of the vertex with h = −b ÷ 2a, then puts it back into the equation to find k. It writes the parabola in vertex form, gives the axis of symmetry, says whether the vertex is a maximum or minimum, and lists the roots, y-intercept, focus and directrix.
Quick explanation: the vertex is the turning point of a parabola.
- a > 0: the parabola opens up and the vertex is the lowest point.
- a < 0: it opens down and the vertex is the highest point.
- Axis of symmetry: the vertical line x = h through the vertex.
How to Use the Vertex Calculator
- Write your equation in the form y = ax² + bx + c.
- Enter a, b and c.
- Press Calculate.
- Read the vertex, vertex form and axis of symmetry.
- Use the roots, focus and directrix if you need them.
Vertex Formulas
- Vertex x-coordinate: h = −b ÷ (2a)
- Vertex y-coordinate: k = f(h) = c − b² ÷ (4a)
- Vertex form: y = a(x − h)² + k
- Focus: (h, k + 1 ÷ (4a)); directrix: y = k − 1 ÷ (4a)
Key Terms
- Parabola: the U-shaped graph of a quadratic function.
- Vertex: the turning point of a parabola, its highest or lowest point.
- Axis of symmetry: the vertical line through the vertex that splits the parabola in half.
- Vertex form: y = a(x − h)² + k, where (h, k) is the vertex.
- Focus and directrix: the point and line that define a parabola: every point on it is the same distance from both.
Worked Example
A ball’s height in metres is y = −x² + 6x − 5. Find the highest point.
- a = −1, b = 6, c = −5
- h = −6 ÷ (2 × −1) = 3
- k = −(3)² + 6(3) − 5 = 4
- The vertex is (3, 4), a maximum because a is negative, and the vertex form is y = −(x − 3)² + 4.
Real-Life Examples
- Lowest point: y = 2x² − 8x + 3 has its minimum at (2, -5).
- Highest point: a ball on y = −x² + 6x − 5 peaks at (3, 4).
- No real roots: y = x² + 4x + 7 has vertex (-2, 3) above the x-axis and opens up, so it never crosses it.
- Profit: profit −2x² + 120x − 1,000 is greatest at x = 30, where it is $800.
Standard Form vs Vertex Form
- Standard form y = ax² + bx + c shows the y-intercept (c) straight away.
- Vertex form y = a(x − h)² + k shows the vertex (h, k) straight away.
- Factored form y = a(x − r₁)(x − r₂) shows the roots; the vertex is halfway between them.
Vertex Examples
| Equation | Vertex | Vertex form | Max or min |
|---|---|---|---|
| y = x² | (0, 0) | y = x² | Minimum |
| y = x² − 6x + 5 | (3, −4) | y = (x − 3)² − 4 | Minimum |
| y = 2x² − 8x + 3 | (2, −5) | y = 2(x − 2)² − 5 | Minimum |
| y = −x² + 6x − 5 | (3, 4) | y = −(x − 3)² + 4 | Maximum |
| y = x² + 4x + 7 | (−2, 3) | y = (x + 2)² + 3 | Minimum |
Completing the Square
You can also reach vertex form by completing the square. For y = 2x² − 8x + 3:
- Take out a from the x terms: y = 2(x² − 4x) + 3
- Add and subtract (4 ÷ 2)² = 4 inside: y = 2(x² − 4x + 4 − 4) + 3
- Make the square: y = 2(x − 2)² − 8 + 3
- Simplify: y = 2(x − 2)² − 5, so the vertex is (2, −5).
Why the Vertex Matters
The vertex answers “highest” and “lowest” questions. For a thrown ball it gives the peak height and when it happens. For a business with profit −2x² + 120x − 1,000, the vertex at x = 30 gives the price or quantity with the most profit. In engineering, the focus of a parabola is where a satellite dish or a headlight reflector gathers or sends out signals.
The vertex also helps you sketch a graph quickly: plot the vertex, draw the axis of symmetry, add the y-intercept and its mirror image, and join them with a smooth U or ∩ shape.
Common Mistakes to Avoid
- Dropping the minus sign. h = −b ÷ 2a, so b = −8 gives h = +8 ÷ 2a.
- Reading vertex form backwards. In y = (x − 3)² + 4, h is +3, not −3.
- Forgetting to find k. Put h back into the original equation.
- Mixing up max and min. Positive a gives a minimum; negative a gives a maximum.
- Using a form that is not standard. Expand and collect terms before reading a, b and c.
Frequently Asked Questions
Use h = −b ÷ 2a for the x-coordinate, then put h into the equation to find k.
Vertex = (−b ÷ 2a, f(−b ÷ 2a)), or (−b ÷ 2a, c − b² ÷ 4a).
Find h and k, then write y = a(x − h)² + k, or complete the square.
A minimum if a is positive and a maximum if a is negative.
The vertical line x = −b ÷ 2a through the vertex.
Yes. Then k = 0 and the parabola touches the x-axis at one point, a repeated root.
Then the equation is a straight line, which has no vertex.
Read it off: in y = a(x − h)² + k the vertex is (h, k).
Average the roots to get h, then find k by putting h into the equation.
They describe the shape; reflectors such as satellite dishes gather signals at the focus.
References & Sources
| Source | Used For | Link |
|---|---|---|
| OpenStax, College Algebra 2e, 5.1 Quadratic Functions | Vertex, vertex form, axis of symmetry and maximum or minimum values. | https://openstax.org/books/college-algebra-2e/pages/5-1-quadratic-functions |
| OpenStax, Precalculus 2e, 8.3 The Parabola | Focus and directrix of a parabola. | https://openstax.org/books/precalculus-2e/pages/8-3-the-parabola |